Posted: 2008-07-03, 15:21 Current Phasor being complex or not
I hope anyone can help me with this. When calculating voltage drops with a cos (Phi) lets say 0.8[**see note at hte bottom]. I am not sure whether I am supposed to calculate the voltage drop like
delta V = I (R cos (Phi) + X sin (Phi))
R being the real impedance and X being the reactive impedance
from what I understand it's agreed upon that "V" will always stay real while "I" can be complex.
does this mean that when I calculate the voltage drop on the reactive part I will write
delta V = I(R sin(Phi) + X cos(Phi))
[**]I hope that people understand this notation. I mean by it that it's the cos of the angle between the real P power(measured in watts) and the complex power S (measured in [VA]).
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